大学MOOC Mechanics of Materials(Central South University)1458218163 最新慕课完整章节测试答案

Unit Test of Chapter 1

1、单选题：
‍The ability of a member to resist failure under external load is the _______ of material.‌
选项：
A:  Strength
B: Stiffness
C: Stability
D: Plastic
答案: 【  Strength】

2、单选题：
‏The capacity of a member to maintain its original equilibrium state under external load is the            .‌
选项：
A: Stiffness
B: Strength
C: Stability
D: Toughness
答案: 【 Stability】

3、单选题：
The assumption of deformed solids in material mechanics does not include            .‏
选项：
A: Continuity hypothesis
B: Uniformity hypothesis
C: Isotropic hypothesis
D: Plane hypothesis
答案: 【  Plane hypothesis】

4、单选题：
‌The stress perpendicular to the section is called           .‏
选项：
A: Total stress
B: Normal stress
C:   Shear stress
D: Principal stress
答案: 【 Normal stress】

5、单选题：
‎What is wrong with the following description of internal forces is               .‎
选项：
A: An internal force is an additional interaction between parts of an object caused by an external force
B: The internal forces are continuously distributed throughout the cross section
C: The internal force varies with the external force
D: An internal force is an interaction between particles in an object
答案: 【 An internal force is an interaction between particles in an object】

6、单选题：
When subjected to a pair of forces of equal magnitude, opposite direction, and the line of action coincident with the axis of the member, the deformation of the member is                .‍‍
选项：
A: Stretch or compression
B: Shear
C: Bend
D: Torsion
答案: 【 Stretch or compression】

7、单选题：
‎Before deformation, the distance between two points A and B on the tensile sample is 100mm. After deformation, the increment of the distance between two points is           mm, so the average linear strain between two points A and B is                .‎
选项：
A:
B:
C:
D:
答案: 【 】

8、单选题：
The basic method to study the internal forces of components in material mechanics is             .​​
选项：
A: Superposition method
B: Method of section
C: Force method
D: Energy method
答案: 【 Method of section】

9、单选题：

‌The figure shows that the triangular thin plate is deformed by external forces. The vertical displacement of the corner at angle B is 0.3mm, but AB and BC remain straight. Given that AC=200mm, the average linear strain along the AB side is             mm.

‌

‌

‌选项：
A:
B:
C:
D:
答案: 【 】

10、单选题：
On the assumption of uniformity, the              of a component is assumed to be the same everywhere.‌
选项：
A: Displacement
B: Stress
C: Strain
D: Modulus of elasticity
答案: 【  Modulus of elasticity】

Unit Test of Chapter 10

1、单选题：
​An axial compressive force F＝Fcr  is acting on an ideal column in linear equilibrium. And then the column produces the bending deformation due to a small lateral disturbing force. If the disturbing force is removed at this time,  (     ) . ‏
选项：
A: The bending deformation will disappear and return to a straight line
B: The bending deformation is reduced and the straight line shape can not be restored
C: The bending state is not changed
D: The bending deformation continues to increase
答案: 【 The bending state is not changed】

2、单选题：
‎If the coefficient of equivalent length of the long column is doubled, the critical pressure of the column will be (     ).‍
选项：
A: Doubled
B: Increased by 4 times
C: One half of the original
D: A quarter of the original
答案: 【 A quarter of the original 】

3、单选题：

‌The area of cross section and material of the 3 columns are different, but their (  ) are the same.

‍

‌

‍选项：
A: Equivalent length
B: Coefficient of equivalent length
C: Flexibility
D: Critical stress
答案: 【 Equivalent length】

4、单选题：
‏Under the same material conditions, as the flexibility increases, (    )​
选项：
A: The critical stress of the long column decreases while that of the medium flexibility bar remains unchanged
B: The critical stress of the intermediate column decreases while that of the large flexibility bar remains unchanged
C: The critical stress of the large and the intermediate column are both decreased
D: The critical stress of the large and the intermediate column are both unchanged
答案: 【 The critical stress of the large and the intermediate column are both decreased】

5、单选题：
‌Among the following conclusions about the critical stress σcr of the compressive column, the correct one is (     )​
选项：
A: The σcr value of the long column is independent of the material
B: The σcr value of the intermediate column is independent of the flexibility
C: The σcr value of the intermediate column is independent of the materia
D: The σcr value of the small flexibility column is independent of the flexibility
答案: 【 The σcr value of the small flexibility column is independent of the flexibility】

6、单选题：

​The cross-sectional area of each column is the same. Under the same conditions, the stability of the column is the best when the column adopts the cross-sectional shape shown in fig. （    ）.

‏

​

‏选项：
A: （a）
B: （b）
C: （c）
D: （d）
答案: 【 （b）】

7、单选题：

‏Four circular shafts with different support conditions as shown in the figure. The diameter and material of each one are the same. The stability of the compressive column in fig.（    ) is the worst.

‍

‏

‍选项：
A: （a）
B: （b）
C: （c）
D: （d）
答案: 【 （a）】

8、单选题：

​

​

​

​

​

​选项：
A: n=4
B: n=3
C: n=2
D: n=1
答案: 【 n=3】

9、单选题：

‌The material and cross-sectional area of each rod shown in fig.(a) are the same, and the force F acts at the point B. If the structure shown in fig. (a) is changed to the structure shown in fig. (b), only the stability of the compressive column is considered, and the rod is a long column. The two permissible external loads [F1]/[F2] is（    ）.

‍

‌

‍选项：
A:
B:
C:
D:
答案: 【 】

10、单选题：

​

‎选项：
A: 248 kN，284kN；
B: 248 kN，248kN；
C: 284 kN，248kN；
D: 284 kN，284kN；
答案: 【 248 kN，284kN；】

Unit Test of Chapter 11

1、单选题：

‍There is a linear elastic bar. Which is subjected to concentrated forces F and 2F on cross sections B and C, which following statement about the strain energy of the bar is correct?（    ）

​

‍

​选项：
A: The strain energy of the bar is the maximum when F is added first on section B and then 2F is added on section C later.
B: The strain energy of the bar is the maximum when 2F is added first on section C and then F is added on section B later.
C: The strain energy of the bar is the maximum when F and 2F are added proportionally at the same time.
D: The strain energy of the rod is the same when F and 2F added in different order.
答案: 【 The strain energy of the rod is the same when F and 2F added in different order.】

2、单选题：

‎The strain energy of the linear elastic material beam is .  When a concentrated force F is applied to the beam. If changing the force F to 2F, and other conditions are the same, the beam’s strain energy is (   )

‏选项：
A:
B:
C:
D:
答案: 【 】

3、单选题：

​

‌选项：
A:
B:
C:
D:
答案: 【 】

4、单选题：

​There is a cantilever beam. When force F is applied to the beam alone, The rotation angle of section B is θ. If adding the moment of couple M first and then adding force F, during the process of adding force F, the moment of couple M (   )

‍

​

‍选项：
A: doesn’t do work
B: does negative work, the vaule is Mθ
C: does positive work, the vaule is Mθ
D: does negative work, the vaule is 0.5Mθ
答案: 【 does negative work, the vaule is Mθ】

5、单选题：
‍In following statements about Castigliano Second Theorem, which one is correct? (    )‏
选项：
A: The Castigliano Second Theorem is not equivalent to unit force method. Castigliano Second Theorem can deal with more kinds of problems than unit force method.
B: The Castigliano Second Theorem can be used not only to calculate the linear displacement of the structure, but also to calculate the section rotation angle.
C: The Castigliano Second Theorem requires that there must be a force applied at the desired displacement.
D: The Castigliano Second Theorem can not deal with problems of given numerical load.
答案: 【 The Castigliano Second Theorem can be used not only to calculate the linear displacement of the structure, but also to calculate the section rotation angle.】

6、单选题：

‍

‎选项：
A:
B:
C:
D:
答案: 【 】

7、单选题：

​Simply supported beam of the linear elastic material is shown in the following figure. A is a sliding hinge support，B is a spring supporting . Assuming the beam and the spring’s strain energy are and , The deflection at C is (     ).

‎

​

‎选项：
A:
B:
C:
D:
答案: 【 】

8、单选题：

​

​选项：
A: Algebraic sum of horizontal displacement and vertical displacement
B: Vector sum of horizontal displacement and vertical displacement
C: Total displacement
D: Linear displacement in the direction of 45 degrees (direction of resultant force)
答案: 【 Algebraic sum of horizontal displacement and vertical displacement】

9、单选题：
‍When using Mohr Integral Method to calculate the beam’s displacement, the bending-moment equation caused by load and unit force should be established respectively. The requirement is（    ）​
选项：
A: The coordinate x should be consistent, while the divided beam segments can be inconsistent .
B: The divided beam segments should be consistent, while the coordinate x can be inconsistent.
C: The coordinate x and the segment of the beam should be both exactly consistent.
D: The coordinate x and the segment of the beam can be inconsistent.
答案: 【 The coordinate x and the segment of the beam should be both exactly consistent.】

10、单选题：

​There is a linear elastic material beam with variable cross section. the beam’s modulus of elasticity is E. If ignoring shearing, the deflection at the mid-span cross section C is (     )

​

​

​选项：
A:
B:
C:
D:
答案: 【 】

Unit Test of Chapter 12

1、单选题：

‏The degree of static indeterminacy of the illustrated structure is (      ).

​

‏

​选项：
A: 1
B: 2
C: 3
D: 4
答案: 【 3】

2、单选题：

‏Release the link in the structure shown in the figure to get a corresponding primary structure. The number of released constraints is (      ).

‌

‏

‌选项：
A: 1
B: 2
C: 3
D: 0
答案: 【 1】

3、单选题：

‍As shown in the figure, for the statically indeterminate beam. Release the redundant constraint to get the primary structure. Which of the following conclusions is incorrect?  (      )

‍

‍

‍选项：
A: Release the vertical constraint at B.
B: Release the horizontal constraint at A.
C: Release the vertical constraint at A.
D: Release the rotation constraint at A.
答案: 【 Release the horizontal constraint at A.】

4、单选题：
‌The essence of canonical equation of the force method is (     ).‎
选项：
A: Equilibrium equation of force
B: Compatibility equation
C: Physical equation
D: Energy conservation equation
答案: 【 Compatibility equation】

5、单选题：
‏Using the unit-load method to calculate the displacement of statically indeterminate structures. Which of the following conclusions is correct?  (     )​
选项：
A: The unit load can only be added to the corresponding primary structure.
B: The unit load can only be added to the original statically indeterminate structure.
C: The Unit load can be added to the corresponding equivalent system.
D: Unit load can be added to the original statically indeterminate structure or the corresponding primary structure.
答案: 【 Unit load can be added to the original statically indeterminate structure or the corresponding primary structure.】

6、单选题：
‎For symmetric structures and symmetric loads. Which of the following conclusions is correct?  (     ) ​
选项：
A: The axial force, shear force and bending moment on the symmetric section must be equal to 0.
B: The axial force and bending moment on the symmetric section must be equal to 0, and the shear force may not be equal to 0.
C: The axial force and bending moment on the symmetric section may not be equal to 0, the shear force must be equal to 0.
D: The axial force, shear force and bending moment on the symmetric section may not be equal to 0.
答案: 【 The axial force and bending moment on the symmetric section may not be equal to 0, the shear force must be equal to 0.】

7、单选题：
‍For symmetric structures and antisymmetric loads. Which of the following conclusions is correct?  (     )‍
选项：
A: The axial force, shear force and bending moment on the symmetric section must be equal to 0.
B: The axial force and bending moment on the symmetric section must be equal to 0, and the shear force may not be equal to 0.
C: The axial force and bending moment on the symmetric section may not be equal to 0, the shear force must be equal to 0.
D: The axial force, shear force and bending moment on the symmetric section may not be equal to 0.
答案: 【 The axial force and bending moment on the symmetric section must be equal to 0, and the shear force may not be equal to 0.】

8、单选题：

‏The spring stiffness coefficient of the spring support at the end B is k